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4b^2+2b-110=0
a = 4; b = 2; c = -110;
Δ = b2-4ac
Δ = 22-4·4·(-110)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1764}=42$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-42}{2*4}=\frac{-44}{8} =-5+1/2 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+42}{2*4}=\frac{40}{8} =5 $
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